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BRAINLIEST! PLEASE HELP! To plate gold onto a base metal, the overall reaction is Au+3(aq) + 3eāˆ’ → Au(s). How many seconds would it take at a current of 3.5 amps to plate out 2.50 grams of gold?
a. 349 s
b. 1049 s
c. 9.5 x 10^-4 s
d. 17.4 s

Respuesta :

The required time it would take at a current of 3.5 amps to plate out 2.50 grams of gold is 1,049 seconds.

How do we calculate the required time?

According to the faraday's second law, equation to calculate the time will be given below:

W = ZIt, where

W = deposit mass = 2.50 grams

Z = equivalent mass / 96500 = 65.6 / 96500 = 0.000679

I = current = 3.5 amp

t = required time = ?

On putting values in above equation, we get

t = (2.50) / (0.000679)(3.5)

t = 1,054 sec = 1,049 s (approx)

Hence required seconds to plate out 2.50 g of gold is 1,049 sec.

To know more about faradays law, visit the below link:
https://brainly.in/question/1850079

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