[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$3500\\ r=rate\to 2\%\to \frac{2}{100}\dotfill &0.02\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases}[/tex]
[tex]A=3500\left(1+\frac{0.02}{1}\right)^{1\cdot 5}\implies A\approx 3864.28~\hfill \underset{earned~interest}{\stackrel{3864.28~~ - ~~3500}{\approx 364.28}}[/tex]
