The value of molar mass of a 98.2 g sample of gas that fills a 50.0-liter container at stp is 80 g/mol.
The ideal gas law can be given as,
[tex]pV=nRT[/tex]
Here, (p) is pressure, (V) is volume, (n) amount of substance, (R) is ideal gas constant and (T) is the temperature.
For the given problem the modified ideal gas law, (written below) can be used.
[tex]PM=dRT[/tex]
Here, (M) is molar mass and (d) is density.
The molar mass of a 98.2 g sample of gas that fills a 50.0-liter container at stp. As the density is ratio of molar mass to volume. Thus,
[tex]d=\dfrac{40}{11.2}\\d=3.57\rm\; g/L[/tex]
The standard value of temperature and pressure is,
[tex]T=273\text{ K}\\p=1\rm\; bar[/tex]
The value of ideal gas constant (R) is 0.0821 atmL per mol K. Put these values in the above formula,
[tex]1\times M=3.57\times0.0821\times273\\M=80\rm\; g/mol[/tex]
Thus, the value of molar mass of a 98.2 g sample of gas that fills a 50.0-liter container at stp is 80 g/mol.
Learn more about the gas law here;
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