Check the picture below.
[tex]sin(\theta )=\cfrac{\stackrel{opposite}{9}}{\underset{hypotenuse}{15}}~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{12}}{\underset{hypotenuse}{15}}~\hfill tan(\theta )=\cfrac{\stackrel{opposite}{9}}{\underset{adjacent}{12}} \\\\\\ cot(\theta )=\cfrac{\stackrel{adjacent}{12}}{\underset{opposite}{9}}~\hfill sec(\theta )=\cfrac{\stackrel{hypotenuse}{15}}{\underset{adjacent}{12}}~\hfill csc(\theta )=\cfrac{\stackrel{hypotenuse}{15}}{\underset{opposite}{9}}[/tex]
