The sample size for part (a) is 2401, and the sample size for part (b) is 1417 if the margin of error is no more than two percentage points and use a confidence level of 95%
It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.
The formula for finding the MOE:
[tex]\rm MOE= Z{score}\times \frac{s}{\sqrt{n} }[/tex]
Where Z_{score} is the z score at the confidence interval
s is the standard deviation
n is the number of samples.
We have:
MOE = 2% = 0.02 and
α = 1-0.95 = 0.05
Let's assume the value of p = 0.5, and q = 0.5
From the table:
Z_(0.05/2) = Z_(0.025) = 1.96
[tex]\rm n = 0.5\times0.5\frac{1.96^2}{0.02^2}[/tex]
n = 2401
For part (b):
p = 18% = 0.18, and q = 0.82
[tex]\rm n = 0.18\times0.82\frac{1.96^2}{0.02^2}[/tex]
n = 1417.5 = 1417
Thus, the sample size for part (a) is 2401, and the sample size for part (b) is 1417 if the margin of error is no more than two percentage points and use a confidence level of 95%
Learn more about the Margin of error here:
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