Is the solution shown below correct? explain. 9x 2=8x2 6x negative 8 x squared 3 x 2 = 0. x = startfraction negative 3 plus-or-minus startroot (3) squared minus (4) (negative 8) (2) endroot over negative 16 endfraction. x = startfraction negative 3 plus-or-minus startroot 9 minus (64) endroot over negative 16 endfraction. x = startfraction 3 plus-or-minus startroot 55 endroot i over 16 endfraction.

Respuesta :

The correct solution of the given quadratic equation was found using the formula.

The given equation is:

[tex]9x+2=8x^{2} +6x[/tex]

[tex]8x^{2} +6x-9x-2=0[/tex]

[tex]8x^{2} -3x-2=0[/tex]....(1)

What is a quadratic equation?

An equation of the form [tex]ax^{2} +bx+c=0[/tex] is called a quadratic equation where [tex]a\neq 0[/tex].

We can solve equation (1) by the formula

[tex]x=\frac{-b+-\sqrt{b^{2} -4ac} }{2a}[/tex]

So, [tex]x=\frac{3+-\sqrt{(-3)^{2} -4(8)(-2)} }{2(8)}[/tex]

[tex]x=\frac{-3+-\sqrt{73} }{16}[/tex]

Hence, the correct solution of the given quadratic equation was found using the formula.

To get more about quadratic equations visit:

https://brainly.com/question/1214333

Answer:

dont know

Step-by-step explanation: