A standard deck of 52 cards contains 13 cards with hearts, 13 with diamonds, 13 with clubs, and 13 with spades. how many 7-card hands are possible with 2 hearts, 2 diamonds, 2 clubs, and 1 spade? assume that the order of the cards does not matter, and use the formula for combinations to find your answer.

Respuesta :

The number of ways of selecting 7-cards with 2 hearts, 2 diamonds, 2 clubs, and 1 spade is 1,169,176.

What are permutation and combination?

A permutation is an act of arranging the objects or elements in order. Combinations are the way of selecting objects or elements from a group of objects or collections, in such a way the order of the objects does not matter.

A standard deck of 52 cards contains 13 cards with hearts, 13 with diamonds, 13 with clubs, and 13 with spades.

The number of ways of selecting 7-cards with 2 hearts, 2 diamonds, 2 clubs, and 1 spade will be

[tex]\rm Number \ of \ ways = \ ^{13}C_2 \times ^{13}C_2 \times ^{13}C_2 \times ^{13}C_1 \\\\Number \ of \ ways = 78 \times 78 \times 78 \times 13 \\\\Number \ of \ ways = 6,169,176[/tex]

The number of ways is 6,169,176.

More about the permutation and the combination link is given below.

https://brainly.com/question/11732255