Since a force of 37 N is applied to the spring, the spring stretches by 9.74 cm
To answer the question, we need to know Hooke's law.
What is Hooke's law?
This states that the force, F on a stretched spring is directly proportional to its extension, x.
So, F ∝ x
Mathematically, F = kx where k = spring constant
The extension of the spring(How much the spring stretches)
Making x subject of the formula, we have
x = F/k
Given that F = 37 N and k = 380 N/m, we have
x = F/k
x = 37 N/380 N/m
x = 0.0974 m
x = 9.74 cm
So, the spring stretches by 9.74 cm
Learn more about stretched spring here:
https://brainly.com/question/12253978
#SPJ1
