[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$88000\\ r=rate\to 1.75\%\to \frac{1.75}{100}\dotfill &0.0175\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &7 \end{cases}[/tex]
[tex]A=88000\left(1+\frac{0.0175}{12}\right)^{12\cdot 7}\implies A=88000\left( \frac{4807}{4800}\right)^{84}\implies A\approx 99459.21[/tex]
