Answer:
Answer:
62.8 \: {m}^{2}62.8m
2
Step-by-step explanation:
Radius of outer circle = 6 m
Width of the track = 2 m
So, radius of inner circle = 6 - 2 = 4 m
Area of the track = Area of outer circle - Area of inner circle
\begin{gathered} = \pi {6}^{2} - \pi {4}^{2} \\ \\ = \pi( {6}^{2} - {4}^{2} ) \\ \\ = 3.14 \times (36 - 16) \\ \\ = 3.14 \times 20 \\ \\ = 62.8 \: {m}^{2} \end{gathered}
=π6
2
−π4
2
=π(6
2
−4
2
)
=3.14×(36−16)
=3.14×20
=62.8m
2
