Answer:
B.
Step-by-step explanation:
[tex]x^2-8x+97=0[/tex]
[tex]x=\frac{-(-8)\pm\sqrt{(-8)^2-4\times1\times97}}{2\times1}\left\{x=\left.\ \frac{-b\pm\sqrt{b^2-4ac}}{2a}\right\}\right.[/tex]
[tex]=\frac{8\pm\sqrt{-324}}{2}[/tex]
[tex]=\frac{8\pm18i}{2}\left\{i^2\right.=-1\Longrightarrow\sqrt{-1}=\left.\ i\right\}[/tex]
[tex]\Rightarrow x_1=4-9i,x_2=4+9i[/tex]
[tex]\therefore Choose\ B.[/tex]
I hope this helps you
:)
