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26-04-2022
Chemistry

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How many grams of potassium iodide (KI) are required to prepare 50 mL of a 0.30 M
solution?

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26-04-2022

Answer:

137 g

Explanation:

Since1 L=103 mLyou can say that your sample must contain 550.0mL solution⋅1.50 moles KI103mL solution=0.825 moles KITo convert the number of moles of potassium iodide to grams, use the molar mass of the compound.0.825moles KI⋅166.003 g1mole KI=137 g−−−−−

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