A light bulb has a resistance of 360 . What is the current in the bulb when it has a potential difference of 120 V across it?

0.33 A
3 A
480 A
43,200 A

Respuesta :

Answer:

333 mAmps      .33 A

Explanation:

v = ir

v/r = i

120 v / 360 ohm = .3333 A