Respuesta :
The pressure to the nearest tenth at the time of the first measurement for this case was 1.82 atm approximately.
What is Boyle's law?
According to the Boyle's law, the pressure of a gas tends to drop as the capacity of the container increases. We can write it symbolically as:
[tex]P_1V_1 = P_2V_2[/tex]
where we have:
[tex]P_1[/tex] and [tex]V_1[/tex] are first pressure and first volume, and:
[tex]P_2[/tex] and [tex]V_2[/tex] are second pressure and second volume.
The complete question is:
" According to Boyle's law, PV = k, what was the pressure to the nearest tenth at the time of the first measurement given the following information?
V₁ = 7,450 mL, P₂ = 8.25 atm, V₂ = 1,645 mL"
So, using the Boyle's rule, we get:
[tex]P_1V_1 = P_2V_2\\\\P_1 = \dfrac{P_2V_2}{V_1}\\\\P_1 = \dfrac{8.25 \times 1645}{7450} \approx 1.82 \: \rm atm[/tex]
Thus, the pressure to the nearest tenth at the time of the first measurement for this case was 1.82 atm approximately.
Learn more about Boyle's rule here:
https://brainly.com/question/23715689
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