Based on given information about pressure from table and geometry of the solid shape, the total volume of the solid shape is approximately 21073.745 cubic centimeters. [tex]\blacksquare[/tex]
How to determine the volume of the solid shape under pressure
In this question we must apply the concepts of pressure (P), in newtons per square meter, cross section area (A), in square meters, and volume (V), in cubic meters, to determine that Let assume that the bottom experiments an uniform pressure due to a reaction force (F), in newtons, from the table, whose formula is described below:
P = F/A = 4 · F /(π · D²) (1)
If we know that F = 4 N and P = 100 N/m², then the diameter of the cylinder is:
[tex]D = 2\cdot \sqrt{\frac{F}{\pi\cdot P} }[/tex]
D ≈ 0.226 m²
And the volume of the solid shape is: (H = 0.45 m)
V = 0.25π · D² · H + (π/12) · D³
V = 0.25π · (0.226 m)² · (0.45 m) + (π/12) · (0.226 m)³
V ≈ 0.021 m³ (21073.745 cm³)
Based on given information about pressure from table and geometry of the solid shape, the total volume of the solid shape is approximately 21073.745 cubic centimeters. [tex]\blacksquare[/tex]
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