Normal Distributions

According to the College Board, the probability that a student forgets to bring their ID with them when they take their SAT is 3%. A random sample of

500 students was selected. Let p-hat be the proportion of the sample which forgot their ID.

1. What is the mean of the sampling proportion?

2. What is the standard deviation of the sampling proportion?

(Round to the nearest thousandth. )

Respuesta :

The mean of the sampling proportion is 0.03 and the standard deviation of the sampling proportion is 0.008 if the probability that a student forgets to bring their ID with them when they take their SAT is 3%. and a random sample of 500 students was selected.

What is the standard deviation?

It is defined as the measure of data disbursement, It gives an idea about how much is the data spread out.

We have:

p = 0.03

n = 500 students

[tex]\rm {\hat p} - Normal[/tex]

So the mean:

[tex]\rm \mu _\hat p \ = \ p \ = \ 0.03[/tex]

For standard deviation:

[tex]\rm \sigma_p = \sqrt{\frac{pq}{m} }[/tex]

q = 1 - p = 1 - 0.03 = 0.97

[tex]\rm \sigma_p = \sqrt{\frac{0.03\times 0.97}{500} }[/tex]

[tex]\rm \sigma_p = 0.008[/tex]

Thus, the mean of the sampling proportion is 0.03 and the standard deviation of the sampling proportion is 0.008 if the probability that a student forgets to bring their ID with them when they take their SAT is 3%. and a random sample of 500 students was selected.

Learn more about the standard deviation here:

brainly.com/question/12402189

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