Find the surface area of the regular pyramid. HELP QUICK!! (Asking again because the commenter DankBoi18 tried to put a virus on my pc)

We will see that the surface area of the triangular pyramid is equal to 170.1 yd^2
Remember that the area of a triangle is equal to:
A = (1/2)*b*h
Where b is the base, and h is the height.
On the triangular pyramid, we have 3 faces with a base of 9 yards and a height of 10 yd, so the area of these 3 faces is:
A = (1/2)*(10 yd)*(9 yd) = 45 yd^2
Also, we can see that the bottom face has a base of 9 yards and a height of 7.8 yards, then its area is:
A' = (1/2)*(9 yd)*(7.8 yd) = 35.1 yd^2
So the total surface area of the pyramid is:
S = 3*A + A' = 3*45 yd^2 + 35.1 yd^2 = 170.1 yd^2
If you want to learn more about pyramids, you can read:
https://brainly.com/question/10042135