If the value of the mean is 79.6923 then the standard deviation is 3.5. Then the correct option is A.
It is the measure of the dispersion of statistical data. Dispersion is the extent to which the value is in a variation.
The following table shows the heights, in inches, of the players on the opening-night roster of the 2015-2016 New York Knicks.
84, 80, 87, 75, 77, 79, 80, 74, 76, 80, 80, 82, 82
The mean will be
N = 13
[tex]\mu = \dfrac{84+ 80+ 87+ 75+ 77+ 79+ 80+ 74+ 76+ 80+ 80+ 82+ 82}{13}\\\\\mu = \dfrac{1036}{13}\\\\\mu = 79.6923[/tex]
Then the standard deviation will be
[tex]\sigma = \sqrt{\dfrac{\Sigma _{i=2}^N (x_i - \mu)^2}{N}}\\\\\sigma = \sqrt{\dfrac{(84-79.6923)^2+(80-79.6923)^2+ ..... + (82-79.6923)^2}{13}}\\\\\sigma = 3.4947128281848 \approx 3.5[/tex]
More about the standard deviation link is given below.
https://brainly.com/question/12402189
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