Answer:
[tex]\tan \theta ~~ \text{and}~~ \tan( \pi - \theta)[/tex]
Step-by-step explanation:
[tex]\textbf{A)}\\\\-\tan \dfrac{3 \pi}4 = - \tan\left(2 \times \dfrac{\pi}2 - \dfrac{\pi}4 \right) = - \left(- \tan \dfrac{ \pi}4 \right) = \tan \dfrac{\pi}4\\\\\textbf{These pairs are equal.}\\\\\\ \textbf{B)}\\\\\tan \left( \dfrac{5 \pi}4 \right) = \tan \left( 2 \times \dfrac{\pi}2 + \dfrac{\pi}4\right) = \tan \dfrac{\pi}4\\\\\textbf{These pairs are equal.}\\\\ \textbf{C)}\\\\\tan \dfrac{\pi}2= - \tan 90^{\circ} = \infty\\\\\\\textbf{These pairs are equal.}\\\\\\ \textbf{D)}\\\\[/tex]
[tex]\tan ( \pi - \theta ) = - \tan \theta \neq \tan \theta\\\\\textbf{These pairs are not equal.}[/tex]
