HELP ASAP PLEASE

The table below shows the weights of Liam's pumpkin, l(w), and
Patricia's pumpkin, p(w), over a four-week period wherew represents
the number of weeks. Liam's pumpkin grows at a constant rate.
Patricia's pumpkin grows at a weekly rate of approximately 52%.
Assume the pumpkins continue to grow at these rates through week 13.
When comparing the weights of both Liam's and Patricia's pumpkins
in week 10 and week 13, which statement is true?
(1) Liam's pumpkin will weigh more in week 10 and week 13.
3) Patricia's pumpkin will weigh more in week 10 and week 13.
(3) Liam's pumpkin will weigh more in week 10, and Patricia's
pumpkin will weigh more in week 13.
4) Patricia's pumpkin will weigh more in week 10, and Liam's
pumpkin will weigh more in week 13.

HELP ASAP PLEASE The table below shows the weights of Liams pumpkin lw and Patricias pumpkin pw over a fourweek period wherew represents the number of weeks Lia class=

Respuesta :

Liam's pumpkin will weigh more in week 10, and Patricia's pumpkin will weigh more in week 13. Then the correct option is C.

What is the linear system?

A Linear system is a system in which the degree of the variable in the equation is one. It may contain one, two, or more than two variables.

The table below shows the weights of Liam's pumpkin, l(w), and Patricia's pumpkin, p(w), over a four-week period which represents the number of weeks.

Liam's pumpkin grows at a constant rate.

Patricia's pumpkin grows at a weekly rate of approximately 52%.

Let x be the number of the week and y be the weight in pounds.

The equation of Liam's pumpkin will be

[tex]\rm y - 2.4 = \dfrac{5.5-2.4}{7-6} (x- 6)\\\\y - 2.4 = 3.1(x- 6)\\\\y = 3.1x - 16.2[/tex]

Then the weight of Liam's pumpkin after 10 weeks will be

y = 3.1 × 10 - 16.2

y = 31 - 16.2

y = 14.8

Then the weight of Liam's pumpkin after 10 weeks will be

y = 3.1 × 13 - 16.2

y = 40.3 - 16.2

y = 24.1

The equation of Patricia's pumpkin will be

[tex]\rm y = a\times (1.52)^{x}[/tex]

For x = 6 and y = 2.5

Then

[tex]\rm 2.5 = a \times 1.52^6\\\\a \ \ = 0.203[/tex]

We have

[tex]\rm y = 0.203 \times (1.52)^{x}[/tex]

Then the weight of Patricia's pumpkin after 10 weeks will be

[tex]\rm y = 0.203 \times (1.52)^{10}\\\\y = 13.36[/tex]

Then the weight of Patricia's pumpkin after 13 weeks will be

[tex]\rm y = 0.203 \times (1.52)^{13}\\\\y = 46.93[/tex]

More about the linear system link is given below.

https://brainly.com/question/20379472

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