Based on the differences in electronegativities, with which atom is francium (Fr) most likely to form an ionic bond?

A. Fr-Cl = 2.46
B. Fr-Se =1.76
C. Fr- At = 1.50
D. Fr-l =1.96

Respuesta :

An ionic bond will be most likely formed between francium and chlorine having an electronegativity difference of 2.46.

What is is an ionic bond?

An ionic bond is formed between to atoms that have a high difference in electronegativity between them. We now have to look out for the atoms that have a very high electronegativity difference. That pair is most likely to form an ionic bond.

Hence, an ionic bond will be most likely formed between francium and chlorine having an electronegativity difference of 2.46.

Learn more about electronegativity: https://brainly.com/question/2060520