One of the particles in an atom is the proton. A proton has a radius of
approximately 1.0 x 10-13 cm and a mass of 1.7 x 10-24 g. Determine the density of
a proton. (Hint: Find the volume of the proton and then divide the mass by the
volume to get the density.)
4
(volume of a sphere = ³; π = 3.14)

Respuesta :

Answer:

Density = 4.06 * 10^14

Explanation:

Givens

r = 1 * 10^-13 cm

m = 1.7 * 10^-24 grams

Formula

V = 4/3 * pi * r^3

D = m/V

Solution

Put the givens into the formula.

V = (4/3) 3.14 * (1 * 10^-13)^3          Find the value for r^3

V = (4/3) 3.14 * 1 * 10^-39               Find the volume. Indicate divide by 3

V = 1.256 10^-38/3

V = 4.1867 * 10^-39

Density = m / v

Density = 1.7*10^-24/4.1867*10^-39  Do the division

Density = .406 * 10^(-24 + 39)

Density = .406 * 10^15 grams/ cm^3

Answer: Density = 4.06 * 10^14