Answer:
We are given a perimeter and three different lengths and we need to determine the corresponding width and area.
The first length that is provided is 2 feet and to get a perimeter of 16 feet which we can then use the perimeter formula to get 2(2 + 6) which gives us a perimeter of 16 feet and a width of 6 feet. We can then get the area by multiplying the length by width which gives us 12 feet squared.
The second length that is given is 4 feet and to get a perimeter of 16 feet which we can then use the perimeter formula to get 2(4 + 4) which gives us a perimeter of 16 feet and a width of 4 feet. We can then get the area by multiplying the length by width which gives us 16 feet squared.
The final length that is given is 5 feet and to get a perimeter of 16 feet which we can then use the perimeter formula to get 2(5 + 3) which gives us a perimeter of 16 feet and a width of 3 feet. We can then get the area by multiplying the length by width which gives us 15 feet squared.
Therefore, the field that would require the most amount of paint (the largest area) is option B, region #2.
Hope this helps!
