Respuesta :
[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]
- Given - a rectangle with length 25 feet and perimeter 80 feet
- To calculate - width of the rectangle
We know that ,
[tex]\bold{Perimeter \: of \: rectangle = 2(l + b)} \\ [/tex]
where b = width / breadth of rectangle
substituting the values in the formula stated above ,
[tex]\bold{80 = 2(25 + b)} \\ \\\bold{ \implies \: 25 + b = \cancel \frac{80}{2} } \\ \\ \bold{\implies \: 25 + b = 40 }\\ \\ \bold{\implies \: b = 40 - 25 }\\ \\\bold{ \implies \: b = 15 \: feet}[/tex]
hope helpful ~
The width of rectangle = 15 feet .
Step-by-step explanation:
Given =
- Perimeter of rectangle = 80
- Length of rectangle = 25 feet
To Find =
- width or Breadth of rectangle.
As we know ,
Perimeter of rectangle = 2× (L + B )
- where L is Length and B is width or Breadth.
Filling values in the formula :-
=> 80 = 2 ( 25 + B )
- we don't know the value of ' B' so we put ' B' as it is .
=> 80/2 = 25 + B
=> 40 = 25 + B
- when we combine like terms one side signs will be changed from + to - .
=> B = 40 - 25
=> B = 15 feet .
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Properties of rectangle :
- It is a quadrilateral
- each angle is 90° .
- sum of angles is 360°
- Opposite sides are equal.
- Diagonals bisect each other.
Perimeter of rectangle = 2× L+B
Area = L×B .