[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
The given sequence is in Arithmetic progression, and we have to find its nth term ~
So, let's get it solved ~
First term of the sequence is :
Common difference is :
Now, if we have to write the 2nd Term with respect to first one, we can write :
similarly ~
Therefore, I similar pattern ~
[tex] \qquad \sf \dashrightarrow \: nth \: term = a + (n - 1)d[/tex]
[tex] \qquad \sf \dashrightarrow \: nth \: term = 2 + (n - 1)2[/tex]
[tex] \qquad \sf \dashrightarrow \: nth \: term = 2(1 + (n - 1))[/tex]
[tex] \qquad \sf \dashrightarrow \: nth \: term = 2(1 + n - 1)[/tex]
[tex] \qquad \sf \dashrightarrow \: nth \: term = 2 n [/tex]
Feel free to ask your doubts, if you have any ~
Answer:
Step-by-step explanation:
from the number sequence above, each term except the first is generated by adding 2 to the term immediately preceding it.
the nth term of the sequence is usually designated Tn, and it's usually a function of n
from the number sequence
T1= 2
T2 = 2+2= 4
T3= 4+2= 6
T4= 6+2= 8
therefore, Tn= 2+2×(n-1)
= 2+2n-2
=2-2+2n= 2n
