[tex]\sf\huge \green{\underbrace{\red{Answer}}}:[/tex]
length is 32yd and width is 16yd
Step-by-step explanation:
Let the width of rectangle(b) be x
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The length of rectangle(l) = 2x
(as it is twice the width)
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Area = 512yd² (given)
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[tex] \sf Area = l ength \times width \\ \\ \\ \sf \implies 512 = 2x \times x \\ \\ \\ \sf \implies 512 = 2 {x}^{2} \\ \\ \\ \sf \implies \frac{512}{2} = {x}^{2} \\ \\ \\ \sf \implies 256 = {x}^{2} \\ \\ \\ \sf \implies \sqrt{256} = x \\ \\ \\ \red{\boxed{ \implies 16 = x}}[/tex]
Width = 16 yd
length = 2×16 = 32 yd
