[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]
[tex] \textsf{Let the angle be x, then it's complement } [/tex][tex] \textsf{will be } [/tex] ~
[tex]\qquad \sf \dashrightarrow \: \dfrac{x}{6} [/tex]
[tex] \textsf{And as we know, sum of complimentary angles } [/tex] [tex] \textsf{measure 90°} [/tex]
[tex]\qquad \sf \dashrightarrow \: x + \dfrac{x}{6} = 90 [/tex]
[tex]\qquad \sf \dashrightarrow \: \dfrac{6x + x}{6} = 90[/tex]
[tex]\qquad \sf \dashrightarrow \: 7x = 90 \times 6[/tex]
[tex]\qquad \sf \dashrightarrow \: x = \dfrac{540}{7} [/tex]
[tex] \textsf{So, the required angle is } [/tex] [tex]{\sf{{\dfrac{540\degree}{7}}}} [/tex]
