The three sets are independent sets and the value of the probability of A∩B∩C is: 0
The sets are given as:
A = {1,2,3}, B = {4,5} and C = {6,7,8}
The total number of elements in the three sets is:
Total = 8
The number of elements of A∩B∩C is 0, because the sets do not have a common element.
So, the probability of A∩B∩C is:
P = 0/8
Evaluate
P = 0
Hence, the probability of A∩B∩C is: 0
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