Guests at a wedding have an appetizer
choice of soup or a salad, an entrée choice
of chicken, steak, or vegetarian, then a
dessert choice of vanilla or chocolate cake.
How many different meals are possible?

Respuesta :

3421880 number of the different meals are possible.

What is the combination?

The arrangement of the different things or numbers in the number of the ways is called as the combination.

It is given that:-

Number of appetizers is 7, the number of entres is 10, and that there's 4 choices of desserts.

So let's take each course by itself. You can choose 1 of 7 appetizers. So we have n = 7 After that, you chose an entre,

so the number of possible meals to this point is

n = 7  x  10 = 70

Finally, you finish off with a dessert, so the number of meals is:

n = 70 x 4 = 280

Therefore the number of possible meals you can have is 280. Note: If the values of 77, 1010 and 44 aren't errors, but are actually correct, then the number of meals is

n = 77 x  1010 x  44 = 3421880

Therefore 3421880 different meals are possible.

To know more about combinations follow

https://brainly.com/question/11732255

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