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3. A female minke whale has a core body temperature of 35°C and a core/blubber interface temperature of 29°C, with an average blubber thickness of 4.0 cm and thermal conductivity of 0.25 W/mK. At what rate is energy lost from the whale's core by conduction from the core/blubber interface through the blubber to the skin? Assume a skin temperature of 12°C and a total body area of 22 m². ​

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onyebuchinnaji

The rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.

Rate of conduction of core/blubber interface

The rate of conduction of core/blubber interface is calculated as follows;

[tex]\frac{Q}{t} = \frac{kA\Delta T}{d}[/tex]

where;

  • k is thermal conductivity = 0.25 W/mk
  • A is the total body area = 22 m²
  • d is thickness of blubber = 4 cm = 0.04 m
  • ΔT is change in temperature

[tex]\frac{Q}{t} = \frac{kA\Delta T}{d} = \frac{kA}{d} (\Delta Ta \ +\Delta Tb)\\\\\frac{Q}{t} = \frac{kA}{d} ((T_1- T_2 \ +\ T_2-T_3)\\\\\frac{Q}{t} = \frac{0.25 \times 22}{0.04} ( 35 - 29 \ + \ 29 - 12)\\\\\frac{Q}{t} = 137.5( 6 + 17)\\\\\frac{Q}{t} = 3,162.5 \ W[/tex]

Thus, the rate at which energy is lost from the whale's core from the core/blubber interface through the blubber to the skin is 3,162.5 W.

Learn more about conduction here: https://brainly.com/question/893656

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