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A woman runs 6.2 km South. She then turns around and runs 9.3 km North and then finally turns around once more and runs 4.3 km South. How far and in what direction is she from where she started? 1.2 km South 1.2 km South 1.5 km North 1.5 km North 3.1 km North 3.1 km North 1.2 km North

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oladayoademosu

So, how far and in what direction is she from where she started is 1.2 km South of where she started.

To answer the question, we need to know what bearing is.

What is bearing?

This is the measure of the location of an object.

  • Now given that the womans runs 6.2 km south. This bearing is -(6.2 km)j.
  • Also, the woman turns around and runs 9.3 km North. This bearing is (9.3)j.
  • Finally, she turns around and runs 4.3 km South. This bearing is -(4.3)j.

So, her net bearing is r = -(6.2 km)j + (9.3 km)j + [(-4.3 km)j]  

= -(6.2 km)j + (9.3 km)j -(4.3 km)j].

= -(1.2 km)j

Since negative j represent South direction, the woman is 1.2 km South of where she started.

So, the woman is 1.2 km South of where she started.

Learn more about bearing here:

https://brainly.com/question/19351991

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