The spinner illustrates a fair probability because it has equal sections and the value of P(Not T)= 5/6
How to determine the probability?
The sample space of the spinner is:
S = {P,Q,R,S,T,U}
Using the sample space, the probability of T is:
P(T) = 1/6
Using the complement probability formula, the probability of not T is:
P(Not T)= 1 - P(T)
So, we have:
P(Not T)= 1 - 1/6
Evaluate
P(Not T)= 5/6
Hence, the value of P(Not T)= 5/6
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