A rubber bouncy ball is dropped from a
height of 101.00 inches onto a hard flat
floor. After each bounce, the ball returns
to a height that is 19% less than the
previous maximum height. What is the
maximum height reached after the 5th
bounce?

Respuesta :

Using a geometric sequence, it is found that the maximum height reached after the 5th bounce is of 43.48 feet.

What is a geometric sequence?

A geometric sequence is a sequence in which the result of the division of consecutive terms is always the same, called common ratio q.

The nth term of a geometric sequence is given by:

[tex]a_n = a_1q^{n-1}[/tex]

In which [tex]a_1[/tex] is the first term.

In this problem, the ball is dropped from a height of 101.00 inches onto a hard flat floor, and after each bounce, the height is 19% less, that is, 81% of the previous height, hence the first term and the common ratio are given by:

[tex]a_1 = 101, q = 0.81[/tex]

Then, the height of the nth bounce is given by:

[tex]a_n = 101(0.81)^{n-1}[/tex]

And the height of the 5th bounce is:

[tex]a_5 = 101(0.81)^{5-1} = 43.48[/tex]

The maximum height reached after the 5th bounce is of 43.48 feet.

More can be learned about geometric sequences at https://brainly.com/question/11847927

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