SUPER EASY POINTS, i also need some clarification on this question... would i be correct?

Answer:
[tex]\bf \sf \dfrac{1}{3}[/tex]
Take points: (6, 2), (3, 1)
[tex]To \ find \ proportionality = \sf \dfrac{y_2-y_1}{x_2-x_1}[/tex]
Insert values
[tex]\rightarrow \sf \dfrac{1-2}{3-6}[/tex]
Simplify
[tex]\rightarrow \sf \dfrac{-1}{-3}[/tex]
Cancel out the negatives
[tex]\rightarrow \sf \dfrac{1}{3}[/tex]
Answer:
B) [tex]\frac{1}{3}[/tex]
Step-by-step explanation:
When y varies directly with x, the relationship is [tex]y=kx[/tex] where [tex]k[/tex] is the constant of proportionality. Hence, [tex]k=\frac{y}{x}[/tex].
So, your answer would not be correct because you did [tex]\frac{x}{y}[/tex] instead of [tex]\frac{y}{x}[/tex], so the correct option would be the reciprocal, or [tex]\frac{1}{3}[/tex].