The ratio of the area of sector abc to the area of sector dbe is 4/3
For sector abc, we have:
Angle = x
Radius = 2r
For sector dbe, we have:
Angle = 3x
Radius = r
The area of a sector is:
[tex]Area =\frac{\theta}{360}* \pi r^2[/tex]
So, we have:
[tex]ABC =\frac{x}{360}* \pi (2r)^2[/tex]
Evaluate
[tex]ABC =\frac{x* \pi r^2}{90}[/tex]
For DBE, we have:
[tex]DBE =\frac{3x}{360}* \pi (r)^2[/tex]
Evaluate
[tex]DBE =\frac{x}{120}* \pi r^2[/tex]
The ratio of both areas is:
[tex]Ratio = \frac{x}{90}* \pi r^2 : \frac{x}{120}* \pi r^2[/tex]
Cancel out the common factors
[tex]Ratio = \frac{1}{90} : \frac{1}{120}[/tex]
Express as fraction
[tex]Ratio = \frac{120}{90}[/tex]
Divide
[tex]Ratio = \frac{4}{3}[/tex]
Hence, the ratio of the area of sector abc to the area of sector dbe is 4/3
Read more about sector areas at:
https://brainly.com/question/1582027
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