Respuesta :

The reaction of the cyclohex‑2‑enone in each of the three reactions is given below.

How to get the reaction?

Draw the product formed from cyclohex‑2‑enone in each of three reactions.

Cyanide is a very hard chelating agent in the first reaction, and according to HSAB theory, it will approach the hard electrophilic core. As a result, it prefers to target the carbonyl atom.

Because R₂CuLi is a soft nucleophile, it attacks the soft electrophilic site in the second reaction, the attack occurs in a 1,4 added pattern. The primary product of this reaction is formed when oxygen encounters the ethyl iodide group.

The nucleophile is created in situ and is soft in character in the third step. As a result, it prefers a Michael adduct.

The reactions are given below.

More about the reaction link is given below.

https://brainly.com/question/17434463

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