The solution to the given indices are 1/2^7, 11^4 and -1/64
Indices expression
Give the following indices expression
[tex]\frac{(2^{-4})^2\times 2^{-5}}{2^{-6}} \\[/tex]
This can be further simplified according to the law of indices as:
[tex]\frac{(2^{-4})^2\times 2^{-5}}{2^{-6}} =\frac{2^{-8-5}}{2^{-6}}[/tex]
Determine the result
[tex]\frac{2^{-8-5}}{2^{-6}} = 2^{-7} = 1/2^7[/tex]
For the indices expression
[tex]11^{-4}\times 11^{8} = 11^{-4+8}=11^4[/tex]
For the indices expression
[tex]-4^4\times4^{-7}\\=-(4^{4-7})\\= -4^{-3}\\=-1/4^3\\=-1/64[/tex]
Hence the solution to the given indices are 1/2^7, 11^4 and -1/64
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