The reactance of the circuit will be 5.233×10⁻⁴ ohm. Inductive reactance is the product of 2 times π frequency and the coil inductance.
When alternating electricity passes through pure reactance, it causes a voltage drop that is 90 degrees out of phase with the current.
The letter “X” is used to represent reactance in mathematics, and it is measured in ohms.
The inductive reactance of a coil is calculated using the following formula:
Inductive reactance, or XL, is the product of 2 times p (pi), and the frequency of the ac current in hertz, and the coil inductance in henries.
XL= 2πfL
Where,
f {frequency)
L (Inductance)
The reactance of the circuit is found as;
[tex]\rm R_{new}=0.38[{(\frac{1}{60} )^2][/tex]
[tex]\rm R_{new}=1.055 \times 10^{-4} \ ohm[/tex]
The inductance of the circuit is;
[tex]\rm X_{new}=1.9(\frac{1}{60} )^2\\\\X_{new}= 5.233 \times 10^{-4}\ ohm[/tex]
Hence, the reactance of the circuit will be 5.233×10⁻⁴ ohm.
To learn more about the reactance, refer to the link;
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