If AB is tangent to (circle)C at A, find BC.

Answer:
BC = 24 in
Step-by-step explanation:
since AB is a tangent to the circle then ∠ BAC = 90°
using the sine ratio in the right triangle and the exact value
sin30° = [tex]\frac{1}{2}[/tex] , then
sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AC}{BC}[/tex] = [tex]\frac{12}{BC}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
BC = 24