The margin of error will be E = ± 4.04 %
The margin of error is defined as the error in the sample data of the statistics.
Given that:-
sample data = ( p ).
success p^ = success percentage = 40 %
confidence interval CI = 98%
sample size n = 800
margin of error E:
E=z-critical [tex]\dfrac{\sqrt{P(P-1)}}{n}[/tex]
The margin of error "E" for estimation of population proportion ( p ) is given by:
P ( Z < Z-critical ) = a/ 2
a = 1 - CI
P ( Z < Z-critical ) = (1 - 0.98) / 2
P ( Z < Z-critical ) = 0.01
Z-critical = 2.33
The error E = ± 4.04 %
Thus, the correct answer is E=± 4.04 %
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