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The addition of 100 g of a compound to 750 g of ccl4 lowedblue the freezing point of the solvent by 10. 5 k. calculate the molar mass of the compound

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pstnonsonjoku

From the calculations and the information provided, the molar mass of the substance is 381 g/Mol.

What is freezing point?

The freezing point of a substance is the temperature at which the liquid is converted to solid.

Thus;

ΔT= K m i

K = freezing constant

m = molality

i = Van't Hoff factor

Given that;

10.5 °C=  29.8 °C/m * m * 1

m =  10.5 °C/29.8 °C/m

m = 0.35 m

Now;

0.35  = 100/MM/0.75

0.35  =100/MM * 1/0.75

0.35 = 100/0.75MM

0.35 * 0.75MM = 100

MM = 100/ 0.35 * 0.75

MM = 381 g/Mol

Learn more about molar mass:https://brainly.com/question/12127540

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