The volume of gas at 265 K is 7.60 L.
The gas equation that has been followed by an ideal gas is an ideal gas equation. It can be given as:
Pressure × Volume = Moles × Gas constant × Temperature
The given gas has:
Substituting the values in the gas equation:
0.9 atm × Volume = 0.323 mol × 0.08 L.atm.K⁻¹.mol⁻¹ × 265 K
Volume = 0.323 mol × 0.08 L.atm.K⁻¹.mol⁻¹ × 265 K / 0.9 atm
Volume = 7.60 L
The volume of gas at 265 K is 7.60 L.
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