Acetic acid has a pka of 4. 8. How many milliliters of 0. 2 m acetic acid and 0. 2 m sodium acetate are required to prepare 1 liter of 0. 1 m buffer solution having a ph of 4. 8?

Respuesta :

The preparation of 1 Liter of a buffer requires 250 mL sodium acetate, 250 mL acetic acid, and 500 mL water.

What is pH?

pH is given as the number of hydrogen ion concentrations in a solution. The pH of the buffer is given as:

pH = pKa + log [A⁻]/[HA]

For the buffer with acetic acid, the pH and pka are 4.8. Thus, the equation is given as:

1 = [A⁻]/[HA]

The moles of buffer is given as:

Moles buffer = Molarity × Volume

Moles buffer = 0.1 M × 1 L

Moles buffer = 0.1 moles

The moles of A⁻, acetate is given as:

The moles of acid = Moles of buffer / 2

Moles of acid = 0.1 moles/ 2

Moles of acid = 0.05 moles

The moles of acid are equivalent to the moles of acetate, thus:

Moles of acetate = 0.05 moles

The volume of 0.2 M acetic acid is given as:

Volume = Moles / Molarity

Volume of acetic acid = 0.05 moles / 0.2 M

Volume of acetic acid = 250 mL

Volume of sodium acetate = 0.05 moles / 0.2 M

Volume of Sodium Acetate = 250 mL

The preparation of 1 Liter of a buffer requires 250 mL sodium acetate, 250 mL acetic acid, and 500 mL water.

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