Respuesta :
The overall efficiency of this plant will be 83%. The plant's efficiency is calculated by dividing work output to that of heat supplied.
What is efficiency of the plant?
The efficiency of the plant is found as the ratio of work output to the heat supplied.
The heat supplied is found as;
Q= m h
Q=30,000 kJ/kg,× 60 tons/h
Q=30,000 ×10³×60×10³/3600
Q=3×10⁷×16.66
Q=180.720×10⁶
Q=180 mw
The overall efficiency of this plant is ;
[tex]\eta = \frac{W}{Q_{supplied}} \\\\ \eta = \frac{150}{{180}} \\\\ \eta=0.833 \\\\ \eta= 83 \%[/tex]
The overall efficiency of this plant will be 83%.
To learn more about efficiency, refer:
https://brainly.com/question/13828557
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