Find the largest interval centered about x = 0 for which the given initial-value problem has a unique solution. (enter your answer using interval notation. ) y'' (tan(x))y = ex, y(0) = 1, y'(0) = 0

Respuesta :

The largest interval which includes x=0 for which a given initial-value problem has a unique solution is (-∞,3).

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The given parameters are:

(x − 3)y'' + 4y = x,

y(0) = 0

y'(0) = 1

Divide the equation (x − 3)y'' + 4y = x through by (x - 3), therefore,

[tex]y''+\dfrac{4y}{x-3} = \dfrac{x}{x-3}[/tex]

Compare the above equation to the following equation,

y" + p(x) y' +  q(x)y = g(x)

Then, you will get,

P(x)=4y/(x-3)

q(x)=0

g(x)=x/(x-3)

The domains of functions p(x) and g(x) are all sets of real values except 3.

This is represented as,

(-∞,3) ∪ (3,∞)

Using the unique existence theorem, we have:

The largest interval that contains x = 0 is (-∞,3).

Hence, the largest interval which includes x=0 for which a given initial-value problem has a unique solution is (-∞,3).

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