Respuesta :

The length of missing sides a = 5 units and b = 5/2 units.

What is Trigonometric ratios?

The six trigonometric ratios are sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec).

In ΔABC,

AB (Base) = [tex]\frac{5\sqrt{3}}{2}[/tex]  ,      BC(Hypotenuse) = a   ,       CA (perpendicular) = b

and ∠ABC = [tex]30^0[/tex]

Now,

tan [tex]30^0[/tex] = perp. / base

tan [tex]30^0[/tex] = b /[tex]\frac{5\sqrt{3}}{2}[/tex] = 2b/[tex]5\sqrt{3}[/tex]

[tex]\frac{1}{\sqrt{3} } = \frac{2b}{5\sqrt{3} }[/tex]

[tex]2b = 5[/tex]

b = 5/2

Similarly, sin [tex]30^0[/tex] = perp. / Hypo.

[tex]sin 30^0 = CA / BC[/tex]

[tex]\frac{1}{2} = \frac{b}{a}[/tex]

a = 2b

a = 2 X 5/2

a = 5.

Thus, the length of missing sides a = 5 units and b = 5/2 units

Learn more about trigonometric ratios from :

https://brainly.com/question/1201366

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