Find the missing side lengths. Leave your answers as radicals in simplest form.

The length of missing sides x = 5 units and y = 5 units.
In ΔABC,
AB (Base) = y , BC(Hypotenuse) = [tex]5\sqrt{2}[/tex] , CA (perpendicular) = x
and ∠ABC = [tex]45^0[/tex]
Now,
tan [tex]45^0[/tex] = perp. / base
1 = x /y
x= y .................(i)
again,
sin [tex]45^0[/tex] = perp. / Hypo.
[tex]\frac{1}{\sqrt{2} } = \frac{x}{5\sqrt{2} }[/tex]
x = 5
put in equation (i), we get
y = 5
Thus, the length of missing side of the given triangle is x = 5 units and y = 5 units.
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