The half-reaction is balancing the reduction-oxidation reaction. The half-reaction of the oxidation of the gaseous hydrogen is, H₂ (g) + O₂ (g) + 2e⁻ ⇒ 2OH⁻.
Oxidation is the increase of the oxidation number or the loosing of electrons to the product formation.
As the gaseous hydrogen gas undergoes oxidation to produce liquid water then the reaction will be shown as:
H₂ (g) + O₂ ⇒ H₂O (aq)
Now balancing the oxygen atoms on both sides:
H₂ + O₂ ⇒ 2H₂O
Now the number of hydrogen is balanced by adding two protons on the reactant side as:
H₂ + O₂ + 2H⁺ ⇒2H₂O
Finally, the number of electrons is balanced as:
H₂ + O₂ + 2H⁺ +2e⁻ ⇒ 2H₂O
For a solution to be basic two hydroxides are added on both sides of the reaction:
H₂ + O₂ + 2H⁺ +2e⁻ +2OH⁻ ⇒ 2H₂O +2OH⁻
Hydrogen and hydroxide ions on the reactant side react to form water as:
H₂ + 2H₂O + O₂ + 2e⁻ ⇒ 2H₂O +2OH⁻
Therefore, the oxidation half-reaction will be H₂ + O₂ + 2e⁻ ⇒ 2OH⁻
Learn more about redox reactions here:
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