(0, 0, 1) is not in the orthogonal complement of X. Then the given statement is false.
Orthogonal complements comprise topological spaces that are perpendicular to each other. The orthogonal counterpart of a subset, regardless of how that is selected, is a domain, that is, a set bounded in terms of taking different combinations. Proposition Assume that is a vector space.
Consider {(0, 0, 1), (0, 1, 1), (1, 1, 1)}
Clearly {u, v, w} is linearly independent .
Let X = span {v, w}
Clearly, a vector v is an orthogonal complement of X. If
<v, x> = 0 ∀ x ∈ X
Here, in R³ we can take the dot product as the inner product.
Consider (0, 1, 1), clearly (0, 1, 1) ∈ X take u·v that is (0, 0, 1)·(0, 1, 1) will be
→ 1 ≠ 0
Therefore, (0, 0, 1) is not in the orthogonal complement of X. Hence, the given statement is false.
More about the orthogonal complement link is given below.
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