Rods ab and bc have diameters of 60 mm and 35 mm, respectively. If a load of p=205 kn is applied to the ring at b, determine the average normal stress in rod ab. Take θ=52o

Respuesta :

The average normal stress in rod ab will be 217.622 kpa. It is the internal resistive force.

What is normal stress?

The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as normal stress. It is denoted by [tex]\rm \sigma[/tex] .

The average normal stress in rod ab.

Diameter of rod AB=60 mm

R=30×10⁻³ m

Area of the rod AB face is ;

A=πr²

A=3.14×(30×10⁻³)²

A=0.0942

The average normal stress in rod ab is found as;

[tex]\rm \sigma = \frac{P}{A} \\\\ \sigma= \frac{205 \times 10^3}{0.942} \\\\\\ \sigma=217.622 \ kPa[/tex]

Hence,the average normal stress in rod ab will be 217.622 kpa.

To learn more about the pressure refer to the link;

https://brainly.com/question/356585

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